Optimal. Leaf size=115 \[ \frac{48 c (b+2 c x)}{5 b^4 \sqrt [4]{b x+c x^2}}-\frac{4 (b+2 c x)}{5 b^2 \left (b x+c x^2\right )^{5/4}}-\frac{48 \sqrt{2} c \sqrt [4]{-\frac{c \left (b x+c x^2\right )}{b^2}} E\left (\left .\frac{1}{2} \sin ^{-1}\left (\frac{2 c x}{b}+1\right )\right |2\right )}{5 b^3 \sqrt [4]{b x+c x^2}} \]
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Rubi [A] time = 0.0435125, antiderivative size = 115, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 13, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.308, Rules used = {614, 622, 619, 228} \[ \frac{48 c (b+2 c x)}{5 b^4 \sqrt [4]{b x+c x^2}}-\frac{4 (b+2 c x)}{5 b^2 \left (b x+c x^2\right )^{5/4}}-\frac{48 \sqrt{2} c \sqrt [4]{-\frac{c \left (b x+c x^2\right )}{b^2}} E\left (\left .\frac{1}{2} \sin ^{-1}\left (\frac{2 c x}{b}+1\right )\right |2\right )}{5 b^3 \sqrt [4]{b x+c x^2}} \]
Antiderivative was successfully verified.
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Rule 614
Rule 622
Rule 619
Rule 228
Rubi steps
\begin{align*} \int \frac{1}{\left (b x+c x^2\right )^{9/4}} \, dx &=-\frac{4 (b+2 c x)}{5 b^2 \left (b x+c x^2\right )^{5/4}}-\frac{(12 c) \int \frac{1}{\left (b x+c x^2\right )^{5/4}} \, dx}{5 b^2}\\ &=-\frac{4 (b+2 c x)}{5 b^2 \left (b x+c x^2\right )^{5/4}}+\frac{48 c (b+2 c x)}{5 b^4 \sqrt [4]{b x+c x^2}}-\frac{\left (48 c^2\right ) \int \frac{1}{\sqrt [4]{b x+c x^2}} \, dx}{5 b^4}\\ &=-\frac{4 (b+2 c x)}{5 b^2 \left (b x+c x^2\right )^{5/4}}+\frac{48 c (b+2 c x)}{5 b^4 \sqrt [4]{b x+c x^2}}-\frac{\left (48 c^2 \sqrt [4]{-\frac{c \left (b x+c x^2\right )}{b^2}}\right ) \int \frac{1}{\sqrt [4]{-\frac{c x}{b}-\frac{c^2 x^2}{b^2}}} \, dx}{5 b^4 \sqrt [4]{b x+c x^2}}\\ &=-\frac{4 (b+2 c x)}{5 b^2 \left (b x+c x^2\right )^{5/4}}+\frac{48 c (b+2 c x)}{5 b^4 \sqrt [4]{b x+c x^2}}+\frac{\left (24 \sqrt{2} \sqrt [4]{-\frac{c \left (b x+c x^2\right )}{b^2}}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt [4]{1-\frac{b^2 x^2}{c^2}}} \, dx,x,-\frac{c}{b}-\frac{2 c^2 x}{b^2}\right )}{5 b^2 \sqrt [4]{b x+c x^2}}\\ &=-\frac{4 (b+2 c x)}{5 b^2 \left (b x+c x^2\right )^{5/4}}+\frac{48 c (b+2 c x)}{5 b^4 \sqrt [4]{b x+c x^2}}-\frac{48 \sqrt{2} c \sqrt [4]{-\frac{c \left (b x+c x^2\right )}{b^2}} E\left (\left .\frac{1}{2} \sin ^{-1}\left (1+\frac{2 c x}{b}\right )\right |2\right )}{5 b^3 \sqrt [4]{b x+c x^2}}\\ \end{align*}
Mathematica [C] time = 0.0129909, size = 50, normalized size = 0.43 \[ -\frac{4 \sqrt [4]{\frac{c x}{b}+1} \, _2F_1\left (-\frac{5}{4},\frac{9}{4};-\frac{1}{4};-\frac{c x}{b}\right )}{5 b^2 x \sqrt [4]{x (b+c x)}} \]
Antiderivative was successfully verified.
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Maple [F] time = 1.42, size = 0, normalized size = 0. \begin{align*} \int \left ( c{x}^{2}+bx \right ) ^{-{\frac{9}{4}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{{\left (c x^{2} + b x\right )}^{\frac{9}{4}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (c x^{2} + b x\right )}^{\frac{3}{4}}}{c^{3} x^{6} + 3 \, b c^{2} x^{5} + 3 \, b^{2} c x^{4} + b^{3} x^{3}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\left (b x + c x^{2}\right )^{\frac{9}{4}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{{\left (c x^{2} + b x\right )}^{\frac{9}{4}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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